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5x+6=4x^2
We move all terms to the left:
5x+6-(4x^2)=0
determiningTheFunctionDomain -4x^2+5x+6=0
a = -4; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·(-4)·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-11}{2*-4}=\frac{-16}{-8} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+11}{2*-4}=\frac{6}{-8} =-3/4 $
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